Re: [Scheme-reports] procedure identity
John Cowan 05 Jun 2013 12:41 UTC
Taylan Ulrich B. scripsit:
> eq? is a (typically) more efficient eqv?,
I have yet to be convinced that `eq?` actually is more efficient
than `eqv?` on the safe types.
--
Real FORTRAN programmers can program FORTRAN John Cowan
in any language. --Ed Post cowan@ccil.org
_______________________________________________
Scheme-reports mailing list
Scheme-reports@scheme-reports.org
http://lists.scheme-reports.org/cgi-bin/mailman/listinfo/scheme-reports
