Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (22 Dec 2010 20:47 UTC)
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Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Peter Kourzanov (23 Dec 2010 09:28 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Andre van Tonder (23 Dec 2010 15:11 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? John Cowan (24 Dec 2010 01:14 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Eli Barzilay (24 Dec 2010 01:40 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (24 Dec 2010 08:55 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? John Cowan (24 Dec 2010 09:20 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (24 Dec 2010 09:26 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? John Cowan (25 Dec 2010 00:32 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Adrien "Pied" Piérard (24 Dec 2010 11:51 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (24 Dec 2010 12:49 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Eli Barzilay (24 Dec 2010 16:04 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Andre van Tonder (24 Dec 2010 18:33 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Adrien "Pied" Piérard (27 Dec 2010 01:59 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? John Cowan (27 Dec 2010 05:51 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Adrien "Pied" Piérard (27 Dec 2010 06:22 UTC)
Re: [Scheme-reports] [r6rs-discuss] case reborn Peter Kourzanov (27 Dec 2010 09:55 UTC)
Re: [Scheme-reports] [r6rs-discuss] do we need to redefine eqv? Peter Kourzanov (29 Dec 2010 12:54 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (24 Dec 2010 12:24 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Eli Barzilay (24 Dec 2010 16:02 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (24 Dec 2010 18:17 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Andre van Tonder (24 Dec 2010 18:44 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Andre van Tonder (24 Dec 2010 18:40 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Peter Kourzanov (24 Dec 2010 20:07 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? John Cowan (24 Dec 2010 20:40 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (24 Dec 2010 22:11 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Shiro Kawai (24 Dec 2010 22:27 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (25 Dec 2010 00:48 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? John Cowan (25 Dec 2010 00:29 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? John Cowan (23 Dec 2010 01:49 UTC)
Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Peter Kourzanov (23 Dec 2010 08:25 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? John Cowan (23 Dec 2010 09:13 UTC)
Re: [r6rs-discuss] [Scheme-reports] redefining eqv? Peter Kourzanov (23 Dec 2010 09:26 UTC)
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Re: [Scheme-reports] [r6rs-discuss] redefining eqv? Eli Barzilay 24 Dec 2010 16:00 UTC

Three hours ago, Peter Kourzanov wrote:
> On Fri, 2010-12-24 at 20:49 +0900, Adrien "Pied" Piérard wrote:
> >
> > I believe that
> >
> > (case-with my-equality-predicate foo
> >  ((bar) quux)
> >  (else rofl)))
>
> That's what I always do in my own code, which could be fine for a
> semi-advanced user that redefines (case) for fun. The problem is
> that the core language will lose its terseness appeal to newbies and
> veterans if you proceed this way... And Eli will be unhappy if he
> accidentally imports "wrong" (case) macro.

Please don't put words in my mouth.  If you're using an implementation
with a module system, then you can define any `case' you want without
affecting my code.

> P.S. Note that both Haskell and Scala have special devices to attack
> this problem (typeclasses resp. mixins). Not sure what ML is doing, but
> OCaml could solve this with its OO system supposedly too.

You're talking about a customized equality predicate, which is not
what `eqv?' is doing.  (The reason that `case' is using `eqv?' in the
first place is to allow efficient compilation, similar to a C
`switch' statement.)

--
          ((lambda (x) (x x)) (lambda (x) (x x)))          Eli Barzilay:
                    http://barzilay.org/                   Maze is Life!

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