Re: [Scheme-reports] More NaN and Infsanity John Cowan (30 Apr 2012 07:43 UTC)
Re: [Scheme-reports] More NaN and Infsanity Peter Bex (30 Apr 2012 09:16 UTC)
Re: [Scheme-reports] More NaN and Infsanity Jussi Piitulainen (30 Apr 2012 10:51 UTC)
Re: [Scheme-reports] More NaN and Infsanity John Cowan (30 Apr 2012 17:02 UTC)
Re: [Scheme-reports] More NaN and Infsanity Jussi Piitulainen (30 Apr 2012 18:40 UTC)
Re: [Scheme-reports] More NaN and Infsanity John Cowan (30 Apr 2012 17:01 UTC)
Re: [Scheme-reports] More NaN and Infsanity Peter Bex (30 Apr 2012 17:34 UTC)

Re: [Scheme-reports] More NaN and Infsanity Peter Bex 30 Apr 2012 09:15 UTC

On Mon, Apr 30, 2012 at 03:41:10AM -0400, John Cowan wrote:
> Peter Bex scripsit:
>
> > What about (rationalize x y) where x or y are nan or inf?
> > The notation seems to indicate that nan is allowed, since it's
> > "real but not rational".  However, that same sentence seems to
> > indicate that rationalizing NaN would be an error.
>
> Rationalizing infinity makes some sense, but rationalizing NaN does not,
> at least not to me.

What would the result be then?  According to the spec, both the
infinities and NaN are rational but not real so infinity is out,
and I don't see any sane value other than infinity (or maybe nan)
as output for, say (rationalize +inf.0 1).

> > On the other hand, R6RS seems to indicate that rationalize is
> > allowed to return +nan.0, see its examples:
>
> Indeed, which cannot be right: both R5RS and R6RS require that the result
> be rational.

So, concretely, what should the behaviour of rationalize be for these
values?

It seems to me that both situations should probably be an error.

Cheers,
Peter
--
http://sjamaan.ath.cx
--
"The process of preparing programs for a digital computer
 is especially attractive, not only because it can be economically
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