Vassil Nikolov scripsit:

>   But I think the latter is (also) because with `apply', the arguments
>   to the function being applied have already been evaluated;

Just so.  So when you call (apply fexpr a b), the variables a and b are
evaluated to S-expressions, and then the fexpr may or may not decide to
evaluate the S-expressions further in terms of some reified environment.

--
John Cowan  cowan@ccil.org    http://ccil.org/~cowan
Big as a house, much bigger than a house, it looked to [Sam], a grey-clad
moving hill.  Fear and wonder, maybe, enlarged him in the hobbit's eyes,
but the Mumak of Harad was indeed a beast of vast bulk, and the like of him
does not walk now in Middle-earth; his kin that live still in latter days are
but memories of his girth and his majesty.  --"Of Herbs and Stewed Rabbit"

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